Here is the program in its final layout:

char*M,A,Z,E=40,J[40],T[40];main(C){for(*J=A=scanf(M=”%d”,&C);

—            E;             J[              E]             =T

[E   ]=  E)   printf(“._”);  for(;(A-=Z=!Z)  ||  (printf(“\n|”

)    ,   A    =              39              ,C             —

)    ;   Z    ||    printf   (M   ))M[Z]=Z[A-(E   =A[J-Z])&&!C

&    A   ==             T[                                  A]

|6<<27<rand()||!C&!Z?J[T[E]=T[A]]=E,J[T[A]=A-Z]=A,”_.”:” |”];}

Note how the two decrement operators suggest an entry and exit to the maze!

Obfuscated C. Great!